F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6
and for domain : 3 x + 6 ≠ 0
3 x ≠ - 6
x ≠ - 2
anwser graph of 3 x - 6, with discontinuity at - 2

6 0

3 years ago

Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If

vesna_86 [32]

Answer:

<h2>The probability is 58 %.</h2>

Step-by-step explanation:

This problem belong to a normal distribution probability.

Mean = 63.6

Standard Deviation = 2.5.

We have to find the probability of a height greater than 63.0.

Due to the normal probability, we need to find the Z score first:

$Z=\frac{x-u}{o}$ ; where x is the height, u is the mean, and o is the standard deviation.

$Z=\frac{63-63.6}{2.5} \\Z= -0.24$

Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.

But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,

6 0

3 years ago

Find the angle measure x in the following figures​

Find the angle measure x in the following figures