Let the point be P, and the masses be located at P1 and P2.
The centre of mass is such that the moments of masses m1 and m2 exert an equal moment at the point P,
and the distance P1P2=d
namely,
m1(mPP1)=m2(mPP2)
The distance of the centre of mass from m1 is therefore
d1=d*m2/(m1+m2)
Similarly, the distance of the centre of mass from m2 is
d2=d*m1/(m1+m2)
Answer:
a=41.8 BC=2.8
Step-by-step explanation:
sin30/6=sinx/8
8*sin30=6sinx
4=6sinx
sin^-1(4/6)
angle a
cosine rule
bc^2=3^2 +5^2-2(3)(5)*cos30
BC^2=
BC=2.83
2.8
<h3>
<u>Answer:</u></h3>
Answer:
<h3>
<u>Step-by-step explanation:</u></h3>
Here a graph of line is given and we need to find the slope. So here we can see that the line intersects y - axis at (0,2) and x - axis at (2,0 ). And we know that the slope of the line is tan∅.
<h3>
<u>Hence </u><u>the</u><u> </u><u>slope </u><u>of</u><u> </u><u>the</u><u> </u><u>line</u><u> </u><u>is</u><u> </u><u>1</u><u>. </u></h3>
Answer:
B- Translate left 3 units down and 2 units, and then reflect over the x-axis.
Step-by-step explanation:
Just completed question. Hope this helps
