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2 years ago

Question 2 What is the correct order of operations to complete a math problem?

1 answer:

amm18122 years ago

6 0

Parentheses,(brackets etc.) Exponent, Multiply/divide doesn’t matter which one. Addition/ subtraction. Doesn’t matter which one. You can remember this with the abbreviation PEMDAS. Please mark Brainliest!!!

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A bag contains 4 red marbles, 2 blue marbles, 1 purple marble, and 3 green marbles.If a single marble is pulled out of the bag,

faust18 [17]

Answer:

4 different outcomes based on color or 10 based on amount.

Step-by-step explanation:

I don't think it is specific enough for a definite answer.

5 0

3 years ago

Read 2 more answers

One fourth the sum of x and ten is identical to x minus 4."

Lynna [10]

Answer and Step-by-step explanation:

We are given the word format of an equation.

Let's right it out in numerical form.

$\frac{1}{4} (x + 10) = x - 4$

The first part says One fourth the sum of x and 10

The sum of x and 10 would be shown as x + 10, and one fourth of that means that $\frac{1}{4}$ is multiplying (x + 10).

In this case, identical would mean equal to.

So, $\frac{1}{4}$ (x + 10) would be = to something.

It says that it is identical to x minus 4 (x - 4).

$\frac{1}{4} (x + 10) = x - 4$ is the equation.

#teamtrees #PAW (Plant And Water)

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2 years ago

Plz help me with these, I don't understand this subject.

Stolb23 [73]

Answer:

Step-by-step explanation:

I might be wrong but it seems right.

4 0

2 years ago

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Y=x+1 and y=-x-3 in graphing,Substitution,and elemination

marysya [2.9K]

$\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)$

$SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)$

$ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)$

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2 years ago

Unit Test Unit Test Active 21 22 Which phrase describes the algebraic expression 6x? O the quotient of 6 and a number the differ

tangare [24]

Answer:

-22

Step-by-step explanation:

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2 years ago

Question 2 What is the correct order of operations to complete a math problem?​

Question 2 What is the correct order of operations to complete a math problem?