Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
Answer:
6 + 2x
Step-by-step explanation:
It would be x + 5.75 because the child ticket is 5.75 less than the adult ticket so to solve how to get the adult ticket you do the opposite
Simplify both sides of the equation
(20)(4)= 4(5x+1)
Simplify
80 = 20x+4
Flip the equation
20x+4 = 80
Subtract 4 from both sides
20x+4-4 = 80-4
20x = 76
Divide both sides by 20
20x/20 = 76/20
x= 3.8
There is one solution in this equation
Answer:
B is correct
Step-by-step explanation:
i think