9 inches * 1 foot / 12 inches
= 3/4 feet deep
Area of the sidewalk:
= the sides of the pool * the width of the sidewalk + the corners of the sidewalk (width * width)
= 2 sides * 6 (feet / side) * 2 feet + 2 sides * 14 (feet / side) * 2 feet + 4 corners * (2 feet * 2 feet / corner)
= 12 feet * 2 feet + 28 feet * 2 feet + 4 * 2 feet * 2 feet
= 24 feet^2 + 56 feet^2 + 16 feet^2
= 96 feet^2
Volume:
= 96 feet^2 * 3/4 feet
= (96 * 3 / 4) feet^3
= (19 * 3) feet^3
= 57 feet^3
To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
x = rcos (θ)
Where "r" is the radius
Likewise y = rsin (θ)
Therefore, in the expression r = 3cos (θ) one can write r as:
r = x / cos (θ)
So:
x / cos (θ) = 3cos (θ)
x = 3cos ^ 2 (θ)
The same for y ...
y = rsin (θ)
y = 3cos (θ) sin (θ).
Finally the correct answer is option 2.
x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
Answer:
The form ax2 + bx + c = 0 is called standard form of a quadratic equation. Before solving a quadratic equation using the Quadratic Formula, it's vital that you be sure the equation is in this form.
Step-by-step explanation:
5.476 rounded to the hundredths place = 5.48