Answer:
The critical value that should be used in constructing the interval is T = 5.8408.
The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 4 - 1 = 3
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 5.8408. This is the critical value.
The margin of error is:
M = T*s = 5.8408*7.99 = 46.668 bushels per acre
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 49.6 - 46.668 = 2.943 bushels per acre.
The upper end of the interval is the sample mean added to M. So it is 49.6 + 46.668 = 96.268 bushels per acre.
The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.
The factoring can be done similarly to a quadratic equation thanks to x^4 being the square value of x^2.
<span>x^4 + 6x^2 - 7
x^4</span><span> - x^2</span> + 7x^2 - 7
(x^4 - x^2) + (<span>7x^2 - 7)
</span>x^2(x^2 - 1) + 7(<span>x^2 - 1)
</span>(x^2 + 7)(x^2 - 1)
<span>(x^2 + 7)(x - 1)(x + 1)
</span>
Factored completely we get: <span>(x^2 + 7)(x - 1)(x + 1)</span>
X4 hm I’m pretty sure that’s it
Answer:
30....:)
Step-by-step explanation:
So looking at the graph. L to the midpoint of K is 15.
lets ignore N.
The graph has a line between k to the midpoint of L. So does L to the midpoint of k, which was 15.
This line means they are parrelel, so we can conlude that they both equal 15.
Adding the two together, we find KL is 30 in length.
The graph says KL is parrelel to JM.
So we can conclude that JM is 30.
<u>That looks like D on your answer sheet</u>
The only thing I am not sure of is what the N has to do with the answer.
They give you the value of N, and say the use N, however you do not need N to find the answer.
I think that the answer is 30, and it is included on the answer sheet as well. But fair warning that N did not have a use in it.
Hope this helps :)
Which set of ordered pairs could be generated by an exponential function?A.(0,0),(1,1),(2,8),(3,27)B.(0,1),(1,2),(2,5),(3,10)C.(
Travka [436]
Answer:
Option D
Step-by-step explanation:
Let an exponential function
Where a=Constant
We know that
Therefore,
Point (0,0) can not be obtained by exponential function.
Hence,option A and C are incorrect.
Substitute (0,1)
Substitute (1,2)
Hence, option B is incorrect.
D.(0,1),(1,3),(2,9),(3,27)
Hence, option D is correct.
