What is the distance between the points (-2, 1) and (3, 1)
1 answer:
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a^2 + b^2 = c^2
a = sqrt(c^2 - b^2) = sqrt (20^2 - 16^2)
= 12
sin = a/c = 12/20
= 3/5
cos = b/c = 16/20
= 4/5
tan = a/b = 12/16
= 3/4
csc = c/a = 20/12
= 5/3
= 1 2/3
sec = c/b = 20/16
= 5/4
= 1 1/4
Answer:
The answer is given below
Step-by-step explanation:
From the diagram below,Let the line AB and CD be parallel line. Let transversal line EF cut AB at Y and transversal line EF cut CD at Z.
The bisector of ∠BYZ and ∠DZY meet at O. Therefore ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2
∠BYZ and ∠DZY are interior angles.
∠BYZ + ∠DZY = 180 (sum of consecutive interior angles)
∠BYZ/2 + ∠DZY/2 = 180/2
∠BYZ/2 + ∠DZY/2 = 90°
In ΔOYZ:
∠YZO + ∠ZYO + ∠YOZ = 180 (sum of angles on a straight line).
But ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2
∠DZY/2 + ∠BYZ/2 + ∠YOZ = 180
90 + ∠YOZ = 180
∠YOZ = 180 - 90
∠YOZ = 90°
Therefore Angle bisectors of the same side interior angles are perpendicular.
