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erastova [34]
3 years ago
9

Help

Mathematics
2 answers:
Rudiy273 years ago
7 0

Answer:

520

Step-by-step explanation:

must be the answer..

Wittaler [7]3 years ago
7 0

Answer:

510 or 500

Step-by-step explanation:

80 + 90 + 60 + 100 + 80 + 100 = 510

80 + 80 + 60 + 100 + 80 + 100 +500

it depends how you learned to round 5's either up down

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The table shows the values of a function f(x).
QveST [7]

Answer:

The average rate of change is =-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

=\frac{f(b)-f(a)}{b-a}

We want to find the average rate of change of the function represented in the table  from x=-2 to x=2.

=\frac{f(2)-f(-2)}{2--2}

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

=\frac{9-25}{2--2}

=\frac{-16}{4}

=-4

3 0
3 years ago
What is the slope-intercept form of the equation of the line ? Please answer !!!!
blsea [12.9K]
Y = -3/2x + 4

I need 20 characters so hi
7 0
4 years ago
-4(-2z + 2) = 6z + 8
Savatey [412]
8z-8=6z+8
8x-6z=8+8
2z=16
Z=8
8 0
3 years ago
Read 2 more answers
Brainlyst for the best answer thank you!
densk [106]
Answer: B

We all know that area= LxW
The width that is being shown is 8ft. The length is 20ft. Therefore, you multiply 8 x 20 which gives you 160ft squared. Hope this this helps :)
6 0
3 years ago
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
3 years ago
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