All categories

2 years ago

Can u pls help me with this question

Mathematics

1 answer:

Tresset [83]2 years ago

3 0

The answer is a b c e

You might be interested in

For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?

Irina-Kira [14]

Answer:

it isn't the equation so it can't be any roots...

Step-by-step explanation:

$(2+1)^2+2=10-6\\4+4+1+2=10-6\\11\neq 4$

7 0

2 years ago

There is a bag filled with 4 blue and 5 red marbles.

Rom4ik [11]

Answer:

I think its 2/9 but im not sure worth a try doe

3 0

2 years ago

What is the Lena equation in the slope intercept form( 2x - y = 7)

Archy [21]

Answer

Step-by-step explanation:x=7+y=2

3 0

2 years ago

Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)

MAXImum [283]

Answer-

The lines are two coinciding lines or the same lines.

Solution-

The given line equations are

the first one,

$\Rightarrow x-5y=0$

the second one,

$\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0$

As we know two line equations $A_1x+B_1y+C_1=0$ and $A_2x+B_2y+C_2=0$ will be,

Parallel if, $\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}$
Coincide if, $\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}$
Intersect if, $\dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}$

As here,

$\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}$

$\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}$

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

4 0

3 years ago

If m∠NOP = 24° and m∠NOQ = 110°, what is m∠POQ?

monitta

Correct answer for the above question is - option B. 86°

Step-by-step explanation:

Given:

∠NOP = 24°

∠NOQ = 110°

∠NOP and ∠POQ are adjacent angles

To Find:

∠POQ = ?

Solution:

Hereby, we can say that ∠POQ lies between line OQ and ON as given (∠NOP and ∠POQ are adjacent angles )

∠NOQ - ∠NOP = ∠POQ

∠POQ = 110° - 24°

∠POQ = 86°

Angle POQ is 86°

Thus we can conclude option B as correct answer.

3 0

2 years ago

Can u pls help me with this question ​

Can u pls help me with this question