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denpristay [2]
3 years ago
15

Choose the model that represents the function shown

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

Where is the picture? So I can help

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Wewaii [24]
9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same

10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.

I hope this helps love! :)
4 0
3 years ago
Plz help super fast​
marshall27 [118]

Answer:

E: L is perpendicular to a line with slope -\frac{3}{2}.

Lines are perpendicular if the negative reciprocal of the slope is equal. For example, the reciprocal of \frac{2}{3} is \frac{3}{2} (remember, to get the reciprocal, simply switch the numerator and the denominator).

So, the negative reciprocal of \frac{2}{3} is -\frac{3}{2}. This represents the slope of a line that is perpendicular.

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3 years ago
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masha68 [24]
Sin 30 = O/H = 1/2
So Sin 30 = 1/2
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Does anyone know how to check my sons search history.
kari74 [83]

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go where they do school on

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You would have to put them into different shapes and the formula for the squares is sides^2 and the formula for the triangles is 1/2(b*h), eventually you will add the numbers together
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