I need help with this please its due today :(

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

$a) \ 6^2 \times 6^3 = 6^{2+3} = 6^5 = 7776\\\\b)\ \frac{(-3)^5 }{(-3)^2} = (-3)^{5-2} = (-3)^3 = -27\\\\c)\ [(-2)^3]^4 = (-2)^{3\times 4} = (-2)^{12} = 4096 \\\\d)\ (\frac{1}{999})^0 = 1, anything \ raise \ to \ zero = 1\\\\e) \ (\frac{4}{3})^{-2} = 4^{-2} \times 3^2 = \frac{9}{16}\\\\f) \ \frac{2^5 \times 2^9}{2^{16}} = 2^{5+9-16} = 2^{-2} = \frac{1}{4}$

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