The answer is $11.25 because 110-8.75÷9
Answer:
i would say d
im sorry if im wrong:(
Step-by-step explanation:
Answer:
Δ MNO ≅ ΔXYZ by AAS postulate.
Step-by-step explanation:
Given:
,
, and YO = NZ.
Consider YO = NZ
Add OZ on both sides
YO + OZ = NZ + OZ
YZ = NO
Consider triangles Δ MNO and ΔXYZ.
Statement Reason
1.
Given
2.
Given
3. YZ = NO ∵ YO = NZ
Therefore, the two triangles Δ MNO and ΔXYZ are congruent to each other from AAS postulate as two corresponding angles and a corresponding side are equal to each other.
L = building side
W = non-building side
P = 2W + L = 42 (note only one L because the other L is the building itself)
Solve for L:
L = 42 - 2W
Area = l*w
Area = (42-2W)W = 42W - 2W2
Let area be y, so y = -2W2 +42W
Note this is a parabola pointing down because the coefficient of the W2 is negative. That makes the vertex the maximum for which we are searching.
Vertex of this parabola is at W=-b/2a, if the quadratic is aW2 + bW + c = 0
a = -2
b = 42
W = -42/(2*-2) = -42/-4 = 10.5
W = 10.5
L = 42-2(10.5) = 42-21 = 21
Area = L*W = 21 * 10.5
A = 220.5 ft2