Answer:
It is a many-to-one relation
Step-by-step explanation:
Given
See attachment for relation
Required
What type of function is it?
The relation can be represented as:
![\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy%5C%5C%20%5C%5C10%5C%5C11%5C%5C4%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Where
and 
Notice that the range has an occurrence of 10 (twice)
i.e.
and 
In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
Answer:
2.56
Step-by-step explanation:
The equation they dive u: d = 16t^2, so in the question they said what's the distance, d, if t = 0.4
So you just have to replace t with 0.4:
d = 16t^2
d = 16(0.4)^2
d = 16(0.16)
d = 2.56
Answer: -18
<u>Explanation:</u>
Average rate of change is slope:
. Need to find the y-coordinates:
g(x) = -x² - 4x
g(6) = -(6)² - 4(6)
= -36 - 24
= -60
⇒ (6, -60)
g(8) = -(8)² - 4(8)
= -64 - 32
= -96
⇒ (8, -96)
m = 
= 
= -18