Answer:
1st one
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are a total of 10 persons (6 teachers + 4 students) from which a committee of 5 is to be formed. This can be done in 10C5 ways.
The number of ways that a committee can be formed with no students in it is to select 5 teachers out of the pool of 6 teachers available. This can be done in 6C5 ways.
Therefore the total number of ways that the committee can be formed with at least one student in it is 10C5 - 6C5.
10C5 = 252
6C5 = 6
Therefore the required number of ways = 246
(-6,-8) i believe but its difficult without a graph in front of me haha
(22)(x3)x54x8x112
Simplifies to:
4x757
=4x757
hope it helps
