Answer:
Answer choice B. 24,840,089
Step-by-step explanation:
At a z-score of 1.80, the percentage of the scores that are better than yours is equal to 3.59%.
<h3>What is a z-score?</h3>
In Mathematics, a z-score is sometimes referred to as a z-value or standard score and it can be defined as a measure of the distance between a raw score and the mean, when standard deviation units are used.
<h3>How to determine the percentage?</h3>
Mathematically, the z-score of a given sample score in a normal distribution can be calculated by using this formula:
Z-score = (x - μ)/σ
Where:
- x represents the sample score.
- σ represents the standard deviation.
- μ represents the mean score.
Since a score of 85 on a test corresponds to a z-score of 1.80, the percentage of the scores that are better than yours is given by:
P(x > 85) = P(z > 1.80)
P(z > 1.80) = 0.0359
P(z > 1.80) = 3.59%.
Read more on z-scores here: brainly.com/question/26714379
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Answer:
<em>Their masses are 100 kg and 90 kg</em>
Step-by-step explanation:
<u>Equations</u>
We'll solve the problem by setting only one variable. Let's call:
x = weight of the heavier boxer
Since the sum of the masses of both boxers is 190 Kg:
190 - x = mass of the lighter boxer.
It's given that 
of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:
Operating:
Multiplying by 5:
Simplifying:
The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.
Their masses are 100 kg and 90 kg
I'm not sure if that's the correct method of finding that (it could be, I was just never shown that kind of method). What I did was multiply everything out, that way you have two numbers vs two equations. Then add those two numbers and turn that into scientific notation.
