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ozzi
3 years ago
6

Does the graph represent a function? Hello plssssssssssss

Mathematics
1 answer:
Vlad [161]3 years ago
3 0
A function means every value of x only has 1 y value.
So, this is not a function.
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Given this is an odd number function, which of the following are equal to O(9)
Bumek [7]
It is 9 because I think It is equaltion to 9
7 0
3 years ago
Please help find and plot the reflection of this. I will mark brainliest
lubasha [3.4K]

Answer:

Look below for coordinates

Step-by-step explanation:

A: -2, 3 to A': -2, -3

B:  5, -2 to B': 5, 2

C:  -5, 1 to C': -5, -1

Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)

7 0
2 years ago
Solve In (2x+3)=7 round to the nearest thousandth
e-lub [12.9K]
To solve this problem you must apply the proccedure shown below:

 1. You have:
<span>
 In(2x+3)=7

 2. Then, you must apply log(e), as below:
</span><span>
 In(2x+3)=ln(e^7)

 3. Now, you obtain:

 2x+3=e^7

 4. Youy must clear the variable "x", as below:

 2x=e^7-3
</span> x=(e^7-3)/2
<span>
 5. Therefore, the value of "x" is:

 x=546.817
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 The answer is: </span>x=546.817<span> </span>
8 0
3 years ago
Write an equation in point slope form for each line<br> Slope is 3 and (-2,-1) is on the line
elena-14-01-66 [18.8K]

Answer:

\huge  \blue{y + 1 = 3(x + 2) } \\

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

From the question we have the final answer as

y + 1 = 3(x + 2)

Hope this helps you

6 0
3 years ago
Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)​
umka2103 [35]

Answer:

<u>GIVEN :-</u>

  • ∠A = 15°
  • Length of AB (hypotenuse) = 60 ft

<u>TO FIND :-</u>

  • Length of BC
  • Length of AC
  • Area of ΔABC

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}

<u>SOLUTION :-</u>

In ΔABC ,

  • \sin 15 = \frac{BC}{60}

=> 0.2588... = \frac{BC}{60}

=> BC = (0.2588....) \times 60 = 15.5291..... ≈ 15.5 ft

  • \cos 15 = \frac{AC}{60}

=> 0.9659..... = \frac{AC}{60}

=> AC = (0.9659.....) \times 60 = 57.9555..... ≈ 58 ft

Area of ΔABC = \frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2

4 0
2 years ago
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