I dont understand.. Could someone help?

Mathematics

1 answer:

bija089 [108]3 years ago

4 0

Answer: a) -6, b) -10, c) -3, d) -98, e) -6, f) 49, g) -3.75 h) -12

Step-by-step explanation: For equations like these, you need to solve to get the variables on their own. For problem a, add 5 to -23 (because 5 is negative, you add to cancel it out to 0) which gives us 3x = -18. Lastly, divide the whole equation by 3 to cancel 3 out so that x is alone: 3x/3 = -18/3. This gives us x = -6 (x is negative 6, not positive because a negative divided by a positive is ALWAYS negative).

Given equations like problem d, in order to get x alone, you need to use the opposite of division to make the problem solveable. In this case, multiply -7(denominator) on BOTH sides of the equation to balance it: (-7)x/-7 + (-7)(-3) = (-7)11. Now, we get x + 21 = -77. Then subtract 21 to -77: x = -98 (it isn't -56 because subtracting a positive and a negative means adding them).

TIP: to make sure your answer is correct, plug in the answers you got into the equation. For a, the answer was -6. 3(-6) -5 = -23. -23 = -23. This is a true statement, so the answer is correct.

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Find the indicated probability. The weekly salaries of teachers in one state are normally distributed with a mean of $490 and a

Alecsey [184]

Given Information:

Mean weekly salary = μ = $490

Standard deviation of weekly salary = σ = $45

Required Information:

P(X > $525) = ?

Answer:

P(X > $525) = 21.77%

Step-by-step explanation:

We want to find out the probability that a randomly selected teacher earns more than $525 a week.

$P(X > 525) = 1 - P(X < 525)\\\\P(X > 525) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 525) = 1 - P(Z < \frac{525 - 490}{45} )\\\\P(X > 525) = 1 - P(Z < \frac{35}{45} )\\\\P(X > 525) = 1 - P(Z < 0.78)\\\\$

The z-score corresponding to 0.78 from the z-table is 0.7823

$P(X > 525) = 1 - 0.7823\\\\P(X > 525) = 0.2177\\\\P(X > 525) = 21.77 \%$

Therefore, there is 21.77% probability that a randomly selected teacher earns more than $525 a week.

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.7, 2.2, 1.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.78 then go for 0.08 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

3 0

3 years ago

Is 4/5 a solution of x<2?

krok68 [10]

Yea it is.4\5 is greater than 2

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3 years ago

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