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dmitriy555 [2]
2 years ago
13

Solve the equation y=2x-4, 3x+y=11​

Mathematics
2 answers:
kari74 [83]2 years ago
6 0

Answer:

Step-by-step explanation:

this system not equation :

y=2x-4 ....(1)

3x+y=11​....(2)

put the value of y by (1)  in to (2) :

3x+2x-4 = 11

add4 : 3x+2x =15

5x=15

x=15/5 = 3

but: y = 2x-4

so :  y =  2(3) -4

y = 6-4=2

Ostrovityanka [42]2 years ago
5 0

Answer:

(3, 2)

Step-by-step explanation:

Given the 2 equations

y = 2x - 4 → (1)

3x + y = 11 → (2)

Substitute y = 2x - 4 into (2)

3x + 2x - 4 = 11

5x - 4 = 11 ( add 4 to both sides )

5x = 15 ( divide both sides by 5 )

x = 3

Substitute x = 3 into (1) for corresponding value of y

y = (2 × 3) - 4 = 6 - 4 = 2

Solution is (3, 2)

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The angles in a triangle are represented by 5x, 8x, and 2x+9. What is the value of x?
Ahat [919]

Answer:

x = 11.4

Step-by-step explanation:

The sum of the angles of any triangle must add up to 180°.  Since we have the expressions for each angle:  5x, 8x, and (2x +9), we can solve for the variable of 'x' by adding the expressions together and setting them equal to 180:

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Use inverse operations: 15x + 9 - 9 = 180 - 9

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3 years ago
Question 20 fast please
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Answer:

Square root of 4 is 2

so  1+\frac{[1+\sqrt{2x-1]}^2 }{4}=4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

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I put an attachment to explain better

   

Step-by-step explanation:

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3 years ago
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