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nikklg [1K]
3 years ago
9

What's the value of x when f(x)=58

Mathematics
1 answer:
Natalka [10]3 years ago
3 0
Infinite, because essentially the graph is going to have a horizontal line because f(x)=58/y=58 just means that the y will remain on 58 but the x can have whatever value.
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Find the prime factorization of each number: <br> 11. 29 <br> 12. 168
Ray Of Light [21]
29 is a prime number.
Factors of 29: 1 , 29

168 is a composite number, therefore you can find the prime factorization for it. Divide prime factors until what is left is a prime number. Use the tree factor. See attached picture:

Prime factorization of 168: 2, 2, 2, 3, 7

7 0
3 years ago
1/4 the difference of 4/6 + 3/12
Soloha48 [4]
The answer would be about 8/12 because you must convert 4/6 into 8/12. 8/12 + 3/12=11/12 
1/4 would be about  3/12, so 11/12 - 3/12=8/12.
5 0
3 years ago
The Newport Crab Company marks the location of its crab pots with colored balloons. They mark every fourth pot with a red balloo
sasho [114]

Answer: There are 310 pots that have three different colored balloons attached.

Step-by-step explanation:

Since we have given that

Number of crab pots in the bay = 600

Part of red balloon = \dfrac{1}{4}

Part of blue balloon = \dfrac{1}{6}

Part of yellow balloon = \dfrac{1}{10}

So, Number of pots that have different colored balloons attached is given by

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8 0
3 years ago
Read 2 more answers
Factor each polynomial 6m^2-15m
stellarik [79]
You can do prime factorization then find common factors to factor out.

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Both terms have 3·m so we can factor it out:

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6 0
3 years ago
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IrinaVladis [17]

Answer:

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Step-by-step explanation:

If point <em>M </em>in the figure lies midway between points P(x_{1},y_{1}) and Q(x_{2},y_{2}), point <em>M</em> is called the midpoint of segment. To find the coordinates of <em>M</em>, we average the x-coordinates and average the y-coordinates of P and Q.

So the the midpoint of the line segment with endpoints at (a,b) and (c,d) is the point with coordinates of

(\frac{a+c}{2},\frac{b+d}{2} )

6 0
2 years ago
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