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2 years ago

Which expression is equivalent to 4x2 - 4x – 3 in factored form?

Mathematics

1 answer:

erastovalidia [21]2 years ago

3 0

Answer:

(2x-3)(2x+1)

Step-by-step explanation:

4x^2 - 4x - 3

we need two numbers that give 12 when multiplied and 4 when subtracted

the numbers are 6 and 2 because 6*2=12 and 6-4=4.

4x^2 - (6-2)x -3

4x^2 -6x +2x -3

take common

2x(2x -3)+1(2x-3)

take (2x-3) as common

(2x-3)(2x*1 + 1*1)

(2x-3)(2x+1)

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Can someone send me the Proportional Relationships Flocabulary AK?

Lady bird [3.3K]

Answer:

https://www.flocabulary.com/unit/proportional-relationships/

Step-by-step explanation:

i dont have the answer key but you can highlight this and go to the link

6 0

2 years ago

Angus has $3,000 he want to invest. What interest rate compounded continuously does an account need to offer so that Angus has $

kaheart [24]

Answer:

The interest rate is 7.58%

Step-by-step explanation:

Compound continuous interest can be calculated using the formula:

A = P $e^{rt}$ , where

A is the future value of the investment, including interest

P is the principal investment amount (the initial amount)

r is the interest rate in decimal

t is the time the money is invested for

∵ Angus has $3,000 he want to invest

∴ P = 3000

∵ The interest rate is compounded continuously

∵ Angus has $5,500 in 8 years

∴ A = 5500

∴ t = 8

→ Substitute them in the rule above to find r

∵ 5500 = 3000 $e^{8r}$

→ Divide both sides by 3000

∴ $\frac{11}{6}$ = $e^{8r}$

→ Insert ㏑ in both sides

∵ ㏑( $\frac{11}{6}$ ) = ㏑( $e^{8r}$ )

→ Remember ㏑( $e^{n}$ ) = n

∴ ㏑( $\frac{11}{6}$ ) = 8r

→ Divide both sides by 8

∴ 0.07576697545 = r

→ Multiply it by 100% to change it to a percentage

∴ r = 0.07576697545 × 100%

∴ r = 7.576697545 %

→ Round it to the nearest hundredth

∴ r ≅ 7.58

∴ The interest rate is 7.58%

3 0

2 years ago

For every $5 Micah saves, his parents give him $10.

Alona [7]

150/5 =30, 30•10=300

8 0

3 years ago

A rectangles width is one third it’s length, and it’s perimeter is 120 m. Find the dimensions of the rectangle

tresset_1 [31]

The length is 45m and the width is 15m. Hope I was able to help

3 0

3 years ago

The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores

NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

$P(T1=0) = e^{-2}$

$P(T1=1) = 2 * e^{-2}$

$P(T1=2) = 2 * e^{-2}$

$P(T1=3) = \frac{4}{3} \, e^{-2}$

$P(T1=4) = \frac{2}{3}\, e^{-2}$

$P(T1=5) = \frac{4}{15}\,e^{-2}$

Lets do the same with a Poisson distribution T2 with mean λ = 3

$P(T2=0) = e^{-3}$

$P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}$

Now, we are ready to compute the probability that X is equal to 5.

$P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2} + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2} + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.0471$

$P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2} + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2} + 0.7*e^{-3}) = 0.0047$

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0

2 years ago