Answer:
A. 0
General Formulas and Concepts:
<u>Pre-Algebra
</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I
</u>
<u>Pre-Calculus
</u>
<u>Calculus
</u>
- Derivatives
- Derivative Notation
- Derivative of csc(x) =
![\frac{d}{dx} [csc(x)] = -csc(x)cot(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%20%3D%20-csc%28x%29cot%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
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<u />
<u />
<u>Step 2: Differentiate</u>
- Differentiate:
![\frac{d}{dx} [csc(x)] = -csc(x)cot(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%20%3D%20-csc%28x%29cot%28x%29)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>:

- Evaluate:

Im pretty sure ur supposed to divide 7 and 45.43 and i did and got 6.49$
Answer:
There are 40 students in the class.
Step-by-step explanation:
We are given the following in the question:
Percentage of class that failed = 15%
Percentage of class that made mistakes but did not fail = 25%
Number of students that got perfect score = 24
Percentage of students that got perfect score =

Let x be the total number of students in the class.
Then, we can write:

Thus, there are 40 students in the class.
Any fraction that is greatwer than 1/1 in simplest form
The probability will be found as follows:
z-score is given by:
z=(x-μ)/σ
where:
mean-μ=9.3
standard deviation-σ=1.1
but
σ/√n=1.1/√70=0.1315
thus the z-score will be:
z=(9.1-9.3)/0.1315
z=-1.5209
thus:
P(x<9.1)=P(z<-1.5209)=0.0643