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3 years ago

Point G is (-8,6) Point J is a reflection of point G and is reflected across the x axis what are the coordinates of point J?

Mathematics

1 answer:

kakasveta [241]3 years ago

7 0

Answer:

(-8, -6)

Step-by-step explanation:

Given the Point G is (-8,6) if Point J is a reflection of point G and is reflected across the x axis, to get the coordinate of point J, we will negate the y coordinate while retaining the x coordinate value

J = (-8, -(6))

J = (-8, -6)

Hence the required coordinate of J is (-8, -6)

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-1.2= y/2.4 -1.7<br> Solve for y

evablogger [386]

${\huge{\boxed{\sf{Question}}$

$-1.2= y\div2.4 -1.7$

Solve for y

${\huge{\boxed{\sf{Answer\:with\:explanation }}}$

let's put our equation first

$-1.2= y\div2.4 -1.7$

Flip the equation

$y\div2.4-1.7=-1.2$

Now follow the rule of $BOMDAS/PEMDAS$

${\huge{\boxed{\sf{BOMDAS }}}$

Brackets

Of multiplication

Division

Addition

Subtraction

${\huge{\boxed{\sf{PEMDAS}}}$

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

_________________________

${\huge{\boxed{\sf{Solve\:the\:equation}}}$

_________________________

$y\div2.4-1.7=-1.2$

${\underline{simplify}}$

$0.416667y-1.7=-1.2$

add $1.7$ to both sides

$0.416667y=0.5$

Divide both sides by $0.416667$

$y=1.2$

${\huge{\boxed{\sf{Answer}}}$

$y$ would equal $1.2$

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4 years ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$