I can’t see the scenario on top so can’t rlly help u out sorry
Answer:
D. x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Leg <em>a</em> = 8
Leg <em>b</em> = <em>x</em>
Hypotenuse <em>c</em> = 10
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 8² + x² = 10²
- Isolate <em>x</em> term: x² = 10² - 8²
- Exponents: x² = 100 - 64
- Subtract: x² = 36
- Isolate <em>x</em>: x = 6
Answer:
990 ways
Step-by-step explanation:
The total number of automobiles we have is 11.
Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)
For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)
For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)
Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways