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Sonbull [250]
3 years ago
6

Helpppppppppppppppppppppppppp

Mathematics
1 answer:
noname [10]3 years ago
6 0

Answer:

F

Step-by-step explanation:

So lets use the process of elimantion to find the answer.

Firs off, we can tell that this is a greater/less than or equal to inequlaity, since there is a inclosed circle, not a open one. So this leaves the top left answer and bottem right answer.

Now, we can see that the graph is from 0-15. X is at 7.

This means its x+8, because the x would be smaller, or possibly even negatibe on this graph.

My theory that can better support my annwer is if we solve for  x:

x+8=15

We can subtract 8 from both sides:

x=7

And as we can see on the inequality, x is at 7 in the graph.

Hope this makes sense and helps!

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What is the radius of a circle that has a circumference of 81 π square inches?
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Step-by-step explanation:

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An isosceles trapezoid with bottom base 26.5 decimeters, top base 8.5 decimeters, and height 9 decimeters. Find the area. a. 238
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Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
2 years ago
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