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murzikaleks [220]
3 years ago
9

Solve the equation. 3 1 m + 4

Mathematics
2 answers:
8090 [49]3 years ago
6 0

Answer:

Step-by-step explanation:

I dont- i dont get it

Also im so so so so so so so sorry i need points so bad-

IrinaK [193]3 years ago
5 0
M would most likely be 2/4 try it
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Find equivalent ways to rewrite the expression 6a^8÷3a^4​
solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0
3 years ago
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Can anyone help with my geometry work ?
sasho [114]

Answer:

what should we do ,...?

Step-by-step explanation:

please write your questions!

6 0
3 years ago
WARNING : NON SENSE ANSWER REPORT TO MODERATOR ​
Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

  • Simplify (\frac{3}{-7} - \frac{11}{21} )

=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

  • Simplify (\frac{9}{5} \div \frac{7}{5} )

=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

=> \frac{9}{5} \times \frac{5}{7}

=> \frac{9}{7}

  • Now, find the product of \frac{9}{7} & \frac{20}{21}

=> \frac{9}{7} \times \frac{20}{21}

=> \frac{180}{147}

3 0
3 years ago
(question is on picture linked)
nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

7 0
3 years ago
Problem PageQuestion An automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 wer
8_murik_8 [283]

Answer:

Probability that the first vehicle selected is a motorcycle and the second vehicle is a van is (24/187) or 0.1283.

Step-by-step explanation:

We are given that an automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 were vans.

Plant managers are going to select two of these vehicles for a thorough inspection. The first vehicle will be selected at random, and then the second vehicle will be selected at random from the remaining vehicles.

As we know that, <u>Probability of any event</u>  =  \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

<u>Now, Probability that the first vehicle selected is a motorcycle is given by;</u>

                   =  \frac{\text{Number of motorcycles}}{\text{Total number of vehicles}}

Here, Number of motorcycles = 16

Total number of vehicles = 16 + 9 + 9 = 34

So, <em>Probability that the first vehicle selected is a motorcycle</em> =  \frac{16}{34}

<u>Similarly, Probability that the second vehicle is a van is given by;</u>

              =   \frac{\text{Number of vans}}{\text{Total number of remaining vehicles}}

Here, Number of vans = 9

And Total number of remaining vehicles after selecting one motorcycle = 34 - 1 = 33

So,<em> Probability that the second vehicle selected is a van</em> =  \frac{9}{33}

Therefore, the probability that the first vehicle selected is a motorcycle and the second vehicle is a van  =  \frac{16}{34}\times \frac{9}{33}

                                               =  \frac{24}{187}  =  <u>0.1283</u>

5 0
3 years ago
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