All categories

3 years ago

Find the volume of the larger one pls

Mathematics

1 answer:

slega [8]3 years ago

8 0

Answer:

284 u^3

Step-by-step explanation:

a b c d e f g h i j k l m n o p q r s t u v w x y z

You might be interested in

Determine whether the polygons are similar. <br><br> Similar<br> Not Similar

kupik [55]

The answer is Not similar

6 0

2 years ago

Read 2 more answers

If someone could please help me I’m confused thanks:)

Sedbober [7]

<h3>Answer: x = 45</h3>

Work Shown:

x+x+90 = 180 .... all three angles of a triangle add to 180

2x+90 = 180

2x = 180-90

2x = 90

x = 90/2

x = 45

This is a 45-45-90 right triangle. We also consider it an isosceles right triangle because the base angles (45) are equal.

3 0

3 years ago

Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b

jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .

So; as each place is fitted with either 0 or 1

$\mathbf{|R|= 2^{10}}$

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

$\mathbf{P(E) = \dfrac{|E|}{|R|}}$

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

$\mathbf{{|E|}=1 }$ ; $\mathbf{|R|= 2^{10}}$

$\mathbf{P(E) = \dfrac{1}{2^{10}}}$

4 0

3 years ago

What is the math function of 3x,=y

vichka [17]

Direct variation. Have a nice day!

4 0

3 years ago

An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

3 years ago