Answer:
Yes a 1:3 ratio
Step-by-step explanation:
Yes triangle A is 3 times bigger than triangle B. So it takes 3 B triangles to make one A triangle.
Answer:
Step-by-step explanation:
The question we have at hand is, in other words,
- where we have to solve for the value of 
If we have to isolate here, then we would have to take the inverse of the following matrix ...
... so that it should be as follows ... 
Therefore, we can conclude that the equation as to solve for " " will be the following,
- First find the 2 x 2 matrix inverse of the first portion,
= 
= 
= 
At this point we have to multiply the rows of the first matrix by the rows of the second matrix,
,
- Simplifying this, we should get ...
... which is our solution.
Y
A raiz quadrada de 14 seria 3.74165738677 ou 3.7
Arredondamos para 4 já q 7 é próximo de 10
Answer:
A) 22812 hotdogs per run
B) 75 runs/yr
C) 4 days in a run
Step-by-step explanation:
We are given;
Production rate;p = 5750 per day
Steady Usage rate;u = 270 per day
Setup cost of hotdog;S = $67
Annual carrying cost (H) = 47 cents = $0.47 per hot dog
No. of Production days; d = 297 days
A) Let's first find the annual demand given by the formula;
Annual demand;D = pd
D = 5750 × 297
D = 1707750 hot dogs/yr
Now, formula for optimal run size is given by;
Q_o = √[(2DS/H) × (p/(p - u))]
Plugging in the relevant values gives;
Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]
Q_o =√520375454.7971209
Q_o = 22812 hotdogs per run
B) formula for Number of runs per year is given as;
No. of Runs = D/Q₀
Thus;
no. of runs = 1707750/22812
no. of runs ≈ 75 runs/yr
C) Length of a run is given by the formula;
Length = Q₀/p
Length = 22812/5750
Length ≈ 4 days in a run
