Answer:
√3
Step-by-step explanation:
cot²(θ) = csc²(θ) -1 . . . . . a relevant identity
= 1/sin²(θ) -1
= (1/(1/2))² -1 = 2² -1 = 3
Then ...
cot(θ) = √3 . . . . . . . . take the square root
Answer:
x = -4
Step-by-step explanation:
Simplifying
2[x + 4] = 2[-8 + -1x] + -2x
Reorder the terms:
2[4 + x] = 2[-8 + -1x] + -2x
[4 * 2 + x * 2] = 2[-8 + -1x] + -2x
[8 + 2x] = 2[-8 + -1x] + -2x
8 + 2x = [-8 * 2 + -1x * 2] + -2x
8 + 2x = [-16 + -2x] + -2x
Combine like terms: -2x + -2x = -4x
8 + 2x = -16 + -4x
Solving
8 + 2x = -16 + -4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4x' to each side of the equation.
8 + 2x + 4x = -16 + -4x + 4x
Combine like terms: 2x + 4x = 6x
8 + 6x = -16 + -4x + 4x
Combine like terms: -4x + 4x = 0
8 + 6x = -16 + 0
8 + 6x = -16
Add '-8' to each side of the equation.
8 + -8 + 6x = -16 + -8
Combine like terms: 8 + -8 = 0
0 + 6x = -16 + -8
6x = -16 + -8
Combine like terms: -16 + -8 = -24
6x = -24
Divide each side by '6'.
x = -4
Simplifying
x = -4
Pythagoras theorem
In your case
Which is
Approximated result 13.45
The inequality graph shown is a graph of x < -6
The correct option is option B because it is the only one whose solution give x<-6
x + 9 < 3
x < 3 - 9
x < -6
Therefore the answer is B
