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Margarita [4]
3 years ago
6

The rate at which sand is poured into a bag is modeled by the function r given by r(t)=15t−2t2, where r(t) is measured in millil

iters per second and t is measured in seconds after the sand begins pouring. How many milliliters of sand accumulate in the bag from time t=0 to time t=2 ?
Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

35 mililiters

Step-by-step explanation:

Given

r(t) = 15t - 2t^2

Required

Accumulated amount from t = 0 to 2

This implies that, we substitute the values of t from 0 to 2 in the function

r(0) = 15*0 - 2*0^2= 0

r(1) = 15*1 - 2*1^2= 13

r(2) = 15*2 - 2*2^2= 22

The accumulated sand (r) is:

t = r(0) + r(1) + r(2)

r = 0 + 13 + 22

r = 35

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