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frozen [14]
3 years ago
13

What is the answer to the math question ?

Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0

Answer:

142 square ft

Step-by-step explanation:

the formula is ;

2(lw+lh + wh)

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Xavier can work no more than 40 hours in a week. He has already worked 24 hours this week. What is the maximum number of 8-hour
MrRissso [65]

Answer:

He can work a maximum of 2 8-hour days for the remainder of the week

Step-by-step explanation:

Firstly, from the question, we are made to know that the maximum work hours is 40 hours.

Now, we know that he has already worked 24 hours this week, the number of hours remains to work will be 40-24 = 16 hours

Now, given that his working hour is 8-hours per day, we want to know the number of days he has to work for the remainder of the week

Mathematically, that would be 16 hours divided by 8-hours days

That is 16/8 = 2

7 0
3 years ago
Read 2 more answers
Determine the value of f (4) if f (x) = 3x -- 1
sleet_krkn [62]

Answer: 11

Step-by-step explanation: plug in 4 for x

3(4) - 1 = 12 - 1 = 11

4 0
3 years ago
The lock on a safe requires a three-digit code to open it. The three digits must each be a number from 0-9 (10 possible numbers)
vovangra [49]
The correct answer is Choice B: 720.

To solve this, you have to use the Fundamental Counting Principal. You find the total number of options for each of the digits, then multiply them together.

For the first one, there are 10 options, then 9 options and finally 8 options.

10 x 9 x 8 = 720
7 0
3 years ago
Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with
worty [1.4K]

Answer:

z

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean \mu =26 kilograms and standard deviation \sigma=4.2 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

X"

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(26,4.2)  

Where \mu=26 and \sigma=4.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

z=\frac{42.6-26}{4.2}=3.95

So then the corresponding z scale would be:

z

7 0
3 years ago
Describe the translation of the function from the parent function f(x) = x².
kkurt [141]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\

\end{array}\\

\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


now, notice the template above... now let's see your function \bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}

so.. what do you think was the shift then?
8 0
3 years ago
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