Answer:
no. of $10 bill =2
no. of $5 bill = 3
no. of $1 bill = 5
Step-by-step explanation:
Let the no. of $10 bill be x
Total value of $10 bill = $10*no. of $10 bill = $10x
Given that
Tanya has one more $5 bill than $10 bills
Thus, no. of $5 bill = x+1
Total value of $5 bill = $5*no. of $5 bill = $5(x+1)
Also Given
she has two more $1 bills than $5 bills
no. of $1 bill = no. of $2 bill + 2 = x+1+2 = x+3
Total value of $2 bill = $2*no. of $2 bill = $1(x+3).
Therefore, total value of all the bill sin terms of x
= 10x + 5(x+1) + 1(x+3)
Given that she has total of $40,
then
10x + 5(x+1) + 1(x+3) = 40
10x + 5x+5 + x+3 = 40
=> 16x + 8 = 40
=> 16x= 40-8=32
=> x = 32/16= 2
Thus,
no. of $10 bill = x = 2
no. of $5 bill = x+1 = 2+1= 3
no. of $1 bill = x+3 = 2+3=5
