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Strike441 [17]
3 years ago
9

Write a linear function f with the given values. F(0)=2 , f(2)=4

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
The equation is f(x) = x + 2
Bad White [126]3 years ago
6 0

Answer:

f(x)=f(x-1)+1 is the answer

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Help quick plz i will make you a brainllest
blsea [12.9K]

Answer: B

Step-by-step explanation:

LJ should corresponds with RQ but it should correspond with PR.

8 0
3 years ago
Read 2 more answers
Sheila bought several bags of balloons and boxes of candles. The candles cost $15 per bix, and the balloons cowt $8 per bag. She
snow_tiger [21]

Answer:

balloons= 9

candles= 8

Step-by-step explanation:

let the number of balloons be x

and candles be y

So

15x+8y=192----------1

x+y=17--------------2

from 2, x= 17-y

put x= 17-y in 1

15( 17-y)+8y=192

255-15y+8y=192

solve for y

-7y=192-255

-7y=-63

x=63/7

x=9

put x= 9 in 1

9+y=17

y= 17-9

y=8.

7 0
3 years ago
Rewrite the expression 2(10+15) using distributive property of multiplication over addition
Gala2k [10]

Answer:

2(10+15)= (2x10)+(2x15) 20+30=50

Step-by-step explanation:

5 0
3 years ago
Describe the set of points z in the complex plane that satisfy the given equation; |z-2|=Re(z).
OLEGan [10]

Answer:

Parabola with vertex at point (1,0) that goes to the right (see attached diagram).

Step-by-step explanation:

Let the complex number z be

z=x+iy,

then

z-2=x+iy-2=(x-2)+iy\\ \\Re\ (z-2)=x-2\\ \\Im\ (z-2)=y\\ \\|z-2|=\sqrt{Re^2\ (z-2)+Im^2\ (z-2)}=\sqrt{(x-2)^2+y^2}

and

Re\ z=x

Thus,

\sqrt{(x-2)^2+y^2}=x

Square it:

(x-2)^2+y^2=x^2\\ \\x^2-4x+4+y^2=x^2\\ \\-4x+4+y^2=0\\ \\y^2=4x-4\\ \\y^2=4(x-1)

This is the equation of parabola with vertex at point (1,0) that goes to the right.

3 0
3 years ago
Need help on #5, please help :)
Gre4nikov [31]
Okay i answered by comment but now i can make an official answer here:

a) i got 5,828.6 grams / about 13lb

b) i got 273,391.48$

hope this helps!
6 0
3 years ago
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