3 years ago

Write a linear function f with the given values. F(0)=2 , f(2)=4

Mathematics

2 answers:

Svetllana [295]3 years ago

7 0

The equation is f(x) = x + 2

Bad White [126]3 years ago

6 0

Answer:

f(x)=f(x-1)+1 is the answer

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Please help!<br> i will reward brainliest

drek231 [11]

Answer:

37.9 degrees

Step-by-step explanation:

Using the law of sines, $\frac{\sin(m\angle C)}{21}=\frac{\sin(47^\text{o})}{25}$ . It follows that $\sin (m\angle C) = \frac{21\sin(47^\text{o})}{25} \approx 0.6143371$ . Therefore, $m\angle C = \sin^{-1}(0.6143371)=37.9^\text{o}$ .

6 0

3 years ago

Read 2 more answers

Derivative of <br> <img src="https://tex.z-dn.net/?f=x%5E%7B3%7D" id="TexFormula1" title="x^{3}" alt="x^{3}" align="absmiddle" c

ch4aika [34]

$f(x)=x^3e^{2x}\\\\f'(x)=(x^3e^{2x})'\qquad\text{use}\ (f\cdot g)'(x)=f'(x)g(x)+f(x)g'(x)\\\\=(x^3)'(e^{2x})+(x^3)(e^{2x})'\\\\\text{use}\ (x^n)'=nx^{n-1}\ \text{and}\ (e^x)'=e^x\ \text{and}\ f'[g(x)]=f'(g(x))\cdot g'(x)\\\\=3x^2e^{2x}+x^3e^{2x}\cdot2\\\\=\boxed{3x^2e^{2x}+2x^3e^{2x}}$