Answer:
If there is homologous chromosomes (metaphase I) or duplicated chromosomes/sister chromatids (metaphase II) in the middle of the cell.
Explanation:
Meiosis involves two series of nuclear divisions grouped into meiosis I and meiosis II. Each division has the same number of stages i.e prophase, metaphase, anaphase, telophase etc. Meiosis I involves the separation of homologous chromosomes i.e similar but non-identical chromosomes from each parent.
On the other hand, meiosis II involves the separation of sister chromatids (duplicated chromosome). Since METAPHASE is generally characterized by the alignment of chromosome at the middle of the cell for separation in the anaphase stage, it means that the difference between metaphase in meiosis I and II will be whether it is homologous chromosomes that are in the middle or sister chromatids.
Therefore, according to this question, I would know if the cartoon is in metaphase I or II if:
- there are homologous chromosomes in the middle of the cell (metaphase I)
- there are sister chromatids in the middle of the cell (metaphase II).
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
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The answer would be thermal insulator, hope it works goodluck