Answer:
Copper is being reduced
Step-by-step explanation:
Since the charge of the copper ion went down (2+ --> 0), we can say that Copper is being reduced. An atom is reduced when electrons are added.
Answer:
Step-by-step explanation:
The applicable formula is ...
s = rθ
where s is the arc length, r is the circle's radius, and θ is the central angle in radians.
Filling in the given values, we find ...
15 = 6θ
θ = 15/6 = 2.5 . . . radians
Pi (π) radians is 180°, so the angle in degrees is ...
2.5(180°/π) ≈ 143.24°
Answer: A
Step-by-step explanation:
If they are similar, that means the proportions for corresponding sides will be the same.
I personally ignore the picture and use the labels of "triangle RST and triangle XYZ" that the problem gives <em>because</em> the XYZ picture is not lined up with the similarity it has with RST.
(A) says that side ST is corresponding with side YZ,
[] Triangle R<u>ST</u> and triangle X<u>YZ</u>
-> Correct
(A) also says that side RT is corresponding with size XZ,
[] Triangle <u>R</u>S<u>T</u> and triangle <u>X</u>Y<u>Z</u>
-> Correct
This means that option A is the correct answer.
Step-by-step explanation:
Although I cannot find any model or solver, we can proceed to model the optimization problem from the information given.
the problem is to maximize profit.
let desk be x
and chairs be y
400x+250y=P (maximize)
4x+3y<2000 (constraints)
according to restrictions y=2x
let us substitute y=2x in the constraints we have
4x+3(2x)<2000
4x+6x<2000
10x<2000
x<200
so with restriction, if the desk is 200 then chairs should be at least 2 times the desk
y=2x
y=200*2
y=400
we now have to substitute x=200 and y=400 in the expression for profit maximization we have
400x+250y=P (maximize)
80000+100000=P
180000=P
P=$180,000
the profit is $180,000
Answer:
$3.34 for each pound of popcorn
Step-by-step explanation:
All we must do, in this case, is divide 8.35 by 2.5.
This equals 3.34.
Therefore, each pound of popcorn cost $3.34.
Don't believe me? To check, just multiply 3.34 by 2.5.
Please let me know if you need help with anything else. :)
