Answer:
im so rorry i dont really understand it tho i could guess but i dont want you to get it wrong
Step-by-step explanation:
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
B
Step-by-step explanation:
Hope this helps!!!
The line which represents the equation x = 5 is a vertical line that passes through any point hax x-coordinate of 5
Then the perpendicular line to this line must be a horizontal line
The equation of any horizontal line is y = b, where
b is the y-coordinate of any point that lies on the line
Since the line passes through the point (-2, 2), then
b = 2
Then the equation of the line is
y = 2
