2 years ago

Plz help need it’s down now

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

4 0

Answer:

A. is Inverse correlation and B. is More money

Step-by-step explanation:

A. the relationship is inverse, which means that the more weeks had past, the less he spent

B. Since he is spending less money each week and he earns the same amount, this means that he is saving more money

You might be interested in

Six trig functions help!

tatiyna

-720+2(360)=0

sin 0=0

cos 0=1

tan 0=0

csc 0=1/0

sec 0=1

cot 0=1/0

5 0

3 years ago

There is 5/6 of an apple pie left from dinner. Tomorrow, victor plans to eat 1/6 of the pie that was left. How much of the whole

Tatiana [17]

If there is 5/6 left and he plans to eat 1/6 you do 5/6-1/6=4/6 of the pie

8 0

3 years ago

Read 2 more answers

Write as an improper fraction 7 2/5

Nana76 [90]

Answer:

37/5

Step-by-step explanation:

4 0

3 years ago

for a coloring activity, Mr. Smith needs 15 boxes of crayons for 25 students. how many boxes does Mrs. Jones need for 30 student

sergejj [24]

18 boxes of crayons for 30 students

8 0

3 years ago

Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,

Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j} = {(1,0), (0,1)}

is a base in $\mathbb{R}^2$

and F is linear, then

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0

3 years ago