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2 years ago

Math surface area help plz

Mathematics

2 answers:

Westkost [7]2 years ago

8 0

They give you the formula. Now let's plug numbers in.

it is A= 1/2 (15+12)8
remember PEMDAS, so parentheses first..
A= 1/2 (27)8
A=1/2(216)
if the 1/2 confuses you, just remember that that fraction is saying one half, and another way to represent halves are 0.5
so
A=108

hope this helps!

Stolb23 [73]2 years ago

3 0

So, use the formula:

$A = .5(8)(27)$

A = 108

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Ann took a taxi home from the airport. The taxi fare was

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Answer:

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Step-by-step explanation:

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2 years ago

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attashe74 [19]

Answer:

4(x-7)^2 - 19

Step-by-step explanation:

Shifting 7 units to the right: 4(x-7)^2 - 16.

3 units down: 4(x-7)^2 - 16 - 3, or 4(x-7)^2 - 19

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2 years ago

(1/27)^x-6=27 Could I please have a step by step as well? Much appreciated!

Andrei [34K]

Answer:

$x = 7$

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

$\frac{1}{ {27}^{x - 8} } = 27$

2) Multiply both sides by 27^x - 8.

$1 = {27} \times 27^{1 + x - 8}$

3) Use the product rule: x^a x^b = x^a+b.

$1 = {27}^{1 + x - 8}$

4) Simplify 1 + x - 8 to x - 7.

$1 = {27}^{x - 7}$

5) Use Definition of Common Logarithm: b^a = x if and only if logb (x) = a.

$log_{27}1 = x - 7$

6) Use Change of Base Rule.

$\frac{ log_1 }{ log{27} } = x - 7$

7) Use rule of 1: log 1 = 0.

$\frac{0}{ log_{27}} = x - 7$

8) Simplify 0/log_27 to 0.

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9) Add 7 to both sides.

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10) Switch sides.

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2 years ago

Mr. Nelson lost one of his students' test

amid [387]

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

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59.2 × 5 = 235 + m

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