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Volgvan
3 years ago
5

Imagine that James has been bowling for over 10 years and never gets any better or any worse. The probability that he will bowl

a strike on any attempt of rolling a bowling ball stays at a constant 55%. During a particular bowling game, what is the probability that James will not bowl a strike until his fourth attempt?
Mathematics
1 answer:
vichka [17]3 years ago
7 0

Answer:

5.01%

Step-by-step explanation:

In order to calculate a sequence of events you need to multiply the probability of each event happening with one another in decimal form. In this scenario, the probability of James bowling a strike is 55% meaning that the probability of James NOT bowling a strike is 45%. We want to know the probability of James NOT bowling a strike for 3 attempts and then bowling a strike on his fourth attempt. We first turn these probabilities into decimal form by dividing them by 100. And then multiply...

55 / 100 = 0.55

45 / 100 = 0.45

0.45 * 0.45 * 0.45 * 0.55 = 0.05011875

Multiply by 100 to get percentage.

0.05011875 * 100 = 5.01%

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The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
2 years ago
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