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Nonamiya [84]
2 years ago
12

At a contest spped a car teavels 75 miles in 60 minutes how far deos the car travel in 18 minutes if you get stuck consider usin

g this table
Mathematics
1 answer:
horrorfan [7]2 years ago
3 0

Answer:

it would travel 22.5 miles in 18 minutes

Step-by-step explanation:

it goes 75 miles in 60 minutes so 1 minute would be 0.8 miles so 18 x 0.8 =22.5

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6 0
3 years ago
Read 2 more answers
a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.​
Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = <u>6.15</u><u> </u><u>N</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>effort</u><u> </u><u>applied</u><u> </u><u>=</u><u> </u><u>6.15</u><u> </u><u>N</u>

<u>Hope</u><u> </u><u>this</u><u> </u><u>answer</u><u> </u><u>helped</u><u> </u><u>you</u><u>.</u><u>.</u>

<u>Please</u><u> </u><u>mark</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>brainliest</u><u> </u>

8 0
1 year ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
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