3 years ago

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Mathematics

1 answer:

algol133 years ago

5 0

The answer is D ;)))((

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What is the solution to –4(8 – 3x) ≥ 6x – 8? x ≥ –4/3 x ≤ –4/3 x ≥ 4 x ≤ 4

bonufazy [111]

what i would do is implant some number under 5 for the X's.

Then work it out as if 3 was x so for instance -4(8-3x3)

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3 years ago

Round 45728 to the nearest hundred

TiliK225 [7]

The answer is 45,700

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3 years ago

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Elimination Method: 6x - 4y = -24 and 4x + 5y = -2

nirvana33 [79]

Answer:

$(-2;-6)$

Step-by-step explanation:

First of all, let's rewrite the first one after dividing both sides by 2.

$\left \{ {{3x-2y=-12\atop {4x+5y=-2}} \right.$

Now, let's pick one you want to eliminate.

Eliminating x: Let's multiply the first one by 4, the second by 3, and subtract one from the other. Rest is simply solving an equation in one variable

$4I-3II : 12x-8y-12x+15y = -48 - (-6)\\7y = -42 \rightarrow y= -6$

Eliminating y: Let's multiply the first by 5, the second by 2, and add them together. Rest is simply solving an equation in one variable

$5I+2II: 15x -10y +8x +10y = -60 +4\\23x = -56 \rightarrow x=-2$

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2 years ago

Need help please asap due 5:30

notsponge [240]

Answer:

5 30 is my guess

Step-by-step explanation:

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3 years ago

Reflect shape A in the line x = -2

choli [55]

Answer:

(-2,-1); (-2,-4); (0,-1); (0,-3); (-1,-4); (-1,-3)

Step-by-step explanation:

Just reflect it starting at x=-2

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3 years ago