How many total bits are required for a direct-mapped cache with 128 blocks and a block size of 8 bytes, assuming a 4GB main memo
1 answer:
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Answer:
see explaination
Explanation:
rolls="1,5,2,3,5,4,4,3,1,1,1,2,3,1,5,6,2"
list1 = list(rolls.split(","))
print("The total # of rolls: {}".format(len(list1)))
j=0
for i in list1:
j+=int(i)
print("Total value of all rolls: {}".format(j))
print("Average roll: {}".format(j/len(list1)))
Please kindly check attachment for program code and output
