food.
I'm a child of God snatching lost souls out of Hell
bake
I go to church
some is to much information to give thx and have a blessed day
Answer:
The answer is below
Explanation:
Suppose end system A wants to send a large file to end system B, the large file is first divided into smaller chunks. Each chunk is then assigned a header forming a packet. Multiple packets are being generated with each of the packet containing a unique destination address in its header.
When a packet arrives at the packet switch, the switch uses the unique destination address that is attached in the header of the packet to determine the link onto which the packet is to be forwarded.
#include <iostream> using namespace std; int isPrimeNumber(int); int main() { bool isPrime; for(int n = 2; n < 100; n++) { // isPrime will be true for prime numbers isPrime = isPrimeNumber(n); if(isPrime == true) cout<<n<<" "; } return 0; } // Function that checks whether n is prime or not int isPrimeNumber(int n) { bool isPrime = true; for(int i = 2; i <= n/2; i++) { if (n%i == 0) { isPrime = false; break; } } return isPrime; }
Answer:
Hi!
Let's make a quick debug of the code:
i j Output
0+0 = 0
0+1 = 1
0+2 = 2
0+3 = 3
1+0 = 1
1+1 = 2
1+2 = 3
1+3 = 4
2+0 = 2
2+1 = 3
2+2 = 4
2+3 = 5
3+0 = 3
3+1 = 4
3+2 = 5
3+3 = 6
4+0 = 4
4+1 = 5
4+2 = 6
4+3 = 7
The total outputs is 20.
Explanation:
In the first iterations of the loop for the final value of the <em>i</em> is 1 and the final condition to stop of the do while is (<em>i</em> < 5) , so the iteration of for continues many times until <em>i</em> break the condition.
(5*4 = 20)
And after that you get 20 outputs.
I hope it's help you.
<h3>a= hybrid computer can perform the function of both analog and digital computer</h3>
