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2 years ago

13

Find the measure of

1 answer:

yaroslaw [1]2 years ago

4 0

Answer:

∠ HGL = 73°

Step-by-step explanation:

KL is a midsegment of the triangle and is parallel to HG, then

∠ KLJ = ∠ HGL ( corresponding angles ), so

9x - 62 = 5x - 2 ( subtract 5x from both sides )

4x - 62 = - 2 ( add 62 to both sides )

4x = 60 ( divide both sides by 4 )

x = 15

Thus

∠ HGL = 5x - 2 = 5(15) - 2 = 75 - 2 = 73°

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12 = -2x = 4y<br> Help please

ivolga24 [154]

Answer:

x=−2y+6

Step-by-step explanation:

Step 1: Add -12 to both sides.

−2x+12+−12=4y+−12

−2x=4y−12

Step 2: Divide both sides by -2.

−2x /−2 = 4y−12/−2

x=−2y+6

6 0

2 years ago

F(x) = 16x^5 <br> Linear or Non linear<br> (NO LINKS PLEASE!)

natulia [17]

Answer:

y = 16x^5

Step-by-step explanation:

3 0

2 years ago

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

sveticcg [70]

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
If x and y coordinates are positive, then the angle lies in the 1st quadrant
If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
If x and y coordinates are negative, then the angle lies in the 3rd quadrant
If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point $(\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})$

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = $\frac{-\sqrt{2} }{2}$

∴ cosФ = $\frac{-\sqrt{2} }{2}$

∵ y-coordinate = $\frac{\sqrt{2} }{2}$

∴ sinФ = $\frac{\sqrt{2} }{2}$

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = $\frac{-\sqrt{2} }{2}$ ÷ $\frac{\sqrt{2} }{2}$

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

Someone please help:( I will really appreciate it

Len [333]

Answer:

What do u need help with I don't get what u need help with

Step-by-step explanation:

4 0

2 years ago

Two sides of a triangle are two consecutive number, whose area is 17.5cm². Find the numbers

AveGali [126]

Answer:

The numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

Step-by-step explanation:

Two numbers are consecutives, when their difference is equal to 1. The area of the triangle is determined by the following formula:

$A = \frac{1}{2}\cdot n \cdot (n+1)$

$A = \frac{1}{2}\cdot (n^{2}+n)$

$A = \frac{n^{2}}{2}+\frac{n}{2}$

$n^{2}+n = 2\cdot A$

Where $n$ is the shortest length of the triangle, measured in centimeters.

And we get the following second-order polynomial:

$n^{2}+n -2\cdot A = 0$ (1)

If we know that $A = 17.5\,cm^{2}$ , then the shortest length of the triangle is:

$n_{1} = 5.437\,cm$ and $n_{2} \approx -6.437\,cm$

Since length is a positive variable, the only possible solution is:

$n\approx 5.437\,cm$

Then, the numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

6 0

2 years ago