area of a triangle is 240 centimetre square and its base is 20 CM then find its height of the triangle

Use the Distributive property to write each expression as an equivalent algebraic expression.

Kryger [21]

Answer:

Step-by-step explanation:

we will use distributive property to write an equivalent expression:

7(-2x)+7(6)

6 0

2 years ago

What is the probability of rolling a number greater than 2 on one roll of a die and a 6 on a second roll of a die?

ch4aika [34]

Explanation:
There are
6
possible outcomes:
{
1
,
2
,
3
,
4
,
5
,
6
}

4
of these outcomes are greater than
2
: {3.4.5.6}#
So the probability of a roll greater than
2
is
4
out of
6

XXX
=
4
6
=

2/3

Mark brainliest please

Hope this helps you
Answer link

8 0

2 years ago

Select all the correct answers.<br> Which equations have infinitely many solutions?

777dan777 [17]

I think it is b and d

4 0

2 years ago

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A drunkard executes a “random walk” in the following way: each minute he takes a step north or southm with probability 1/2 each,

valentina_108 [34]

Assume that a step to the north is in the positive direction and a step in the south is in the negative direction.

Then,

$E(X_i)=50\left(\frac{1}{2}\right)-50\left(\frac{1}{2}\right)\\ \\=25-25=0$

and

$\sigma^2(X_i)=E(X_i^2)-E(X_i)^2 \\ \\ =50^2\left(\frac{1}{2}\right)+50^2\left(\frac{1}{2}\right)-0^2=2500\left(\frac{1}{2}\right)+2500\left(\frac{1}{2}\right)-0 \\ \\ =2500 \\ \\ \Rightarrow\sigma(X_i)=50$

After 1 hour of independent steps,

$E(X)=\sum_{i=1}^{60}E(X_i)=60(0)=0$

and

$\sigma^2(X)=\sum_{i=1}^{60}\sigma^2(X_i) \\ \\ =60(50)=300 \\ \\ \Rightarrow\sigma(X)=\sqrt{300}=17.32$

Therefore, by Central Limit Theorem, the distribution of the random walk is normal with a mean of 0 cm and a standard deviation of 17.32 cm. He is expected to be somewhere around his starting point after 1 hour.

6 0

2 years ago

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He loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a p

chubhunter [2.5K]

Complete question :

The loudness of a jack hammer is 96 dB. Its sound intensity is about 0.004.

The loudness of a compactor is 94 dB. Its sound intensity is about 0.0025.

The sound intensity of the jack hammer is about 1.6 times the sound intensity of the compactor.

The loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a pile driver? Round to the nearest ten.

Answer:

40

Step-by-step explanation:

Given that:

Sound intensity of jackhammer = 0.004

Sound intensity of compactor = 0.0025

Sound intensity of jackhammer is about 1.6 times the sound intensity of a compactor

Each factor of 10 in intensity corresponds to 10dB

Pile driver with loudness of 112dB ; 112 / 10 = 11.2

Hence, 10^11.2 = 1.58489 * 10^11

Hence, sound intensity (I) in watts per m²

I = 1.58489 * 10^11 * 10^-12

I = 1.58489 * 10-1

I = 0.158489

Comparing the intensity of pile driver and jackhammer :

Intensity of piledriver / Intensity of jackhammer

0.158489 / 0.004

= 39.622

= 40 (nearest ten)

3 0

2 years ago

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area of a triangle is 240 centimetre square and its base is 20 CM then find its height of the triangle​

area of a triangle is 240 centimetre square and its base is 20 CM then find its height of the triangle