C is false because 30 is both divisible by 5 (30/5=6) and 10 (30/10=3) and is also divisible by 6 since 6*5 is 30
The answer looks like it's A.
10,000 to 100 times 100. And 514 to 1000 minus 486.
Answer:
yes
Step-by-step explanation:
Hi there!
We want to see if 9, 40, and 41 can be the sides of a triangle that can exist
We can use triangle inequalities to figure that out
For triangle inequalities, if the lengths of the sides are a, b, and c, then a+b>c, b+c>a, and c+a>b, then the lengths can make a triangle
Let's say that a=9, b=40, and c=41
Now substitute these values into the inequalities:
a+b>c
9+40>41
49>41
This is a true statement.
b+c>a
40+41>9
81>9
This is also a true statement.
41+9>40
50>40
This is a true statement as well.
Since all three of the inequalities ended up being true (all three NEED to be true in order for the given lengths to make a triangle), then we can confirm that 9, 40, and 41 can make a triangle
Hope this helps!
See more on this topic here: brainly.com/question/17357347
Simplifying
8 + 6t = 3t + t
Combine like terms: 3t + t = 4t
8 + 6t = 4t
Solving
8 + 6t = 4t
Solving for variable 't'.
Move all terms containing t to the left, all other terms to the right.
Add '-4t' to each side of the equation.
8 + 6t + -4t = 4t + -4t
Combine like terms: 6t + -4t = 2t
8 + 2t = 4t + -4t
Combine like terms: 4t + -4t = 0
8 + 2t = 0
Add '-8' to each side of the equation.
8 + -8 + 2t = 0 + -8
Combine like terms: 8 + -8 = 0
0 + 2t = 0 + -8
2t = 0 + -8
Combine like terms: 0 + -8 = -8
2t = -8
Divide each side by '2'.
t = -4
Simplifying
t = -4