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2 years ago

Pls help me I neeed help plssssss

Mathematics

2 answers:

Ierofanga [76]2 years ago

8 0

I believe it could be the third answer.

HACTEHA [7]2 years ago

8 0

Answer:

The third choice

Step-by-step explanation:

Answer choice 1 is incorrect because 72 + a negative number = 6 and it can’t be a negative number.

Answer choice 2 is incorrect because if we subtract 6 from 72, it doesn’t do anything about the number of people on each team.

Answer choice 4 is incorrect because 72 times a fraction = 6 and we know it can’t be a fraction because a fraction of a person… well, let’s not go there.

Therefore, the answer is choice 3.

I hope this helped and please mark me as brainliest!

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I need help for this, thanks

gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

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(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0

3 years ago

It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de

scoray [572]

Answer:

a) $P(X$

$P(z$

b) $P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

$P(z>-0.583)=1-P(Z$

c) $P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) $z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

$X \sim N(72000,12000)$

Where $\mu=72000$ and $\sigma=12000$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table and we got:

$P(z$

Part b

$P(X>65000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>-0.583)=1-P(Z$

Part c

$P(X>100000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.1$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

5 0

3 years ago

Steven wants to fill a 20gallon tank with water. If he uses2 1/2 gallon container to fill the tank, how many times must the cont

aliina [53]

Answer:8

Step-by-step explanation:

2 1/2 +2 1/2 + 2 1/2 + 2 1/2 + 2 1/2 + 2 1/2 + 2 1/2 + 2 1/2=20

5 0

2 years ago

Read 2 more answers

A fountain is made up of two semicircles and a quarter circle. Find the perimeter of the fountain. Round answers to nearest tent

AlexFokin [52]

Answer:

39.275

Step-by-step explanation:

the diameter of the semicircle is 10

A semicircle is half a circle, and a quarter circle is 1/4 of a circle.

Perimeter of a semicircle is ¶d/2

= 3.142 x 10/2 = 3.142 x 5 = 15.71

For 2 semicircles that will be 15.71 x 2 = 31.42

For the quarter circle, perimeter is ¶d/4 = 3.142 x 10/4 = 3.142 x 2.5 = 7.855

Total perimeter = 31.42 + 7.855 = 39.275

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3 years ago

A building has a height of 100ft and a length of 100ft. An architect wants to add to the building by doubling the length of the

skelet666 [1.2K]

That would be 200ft sir

5 0

3 years ago