If the length of a rectangle in terms of x is x^2+2x-3 and its width is 2x^2+3x+5, what is the perimeter of this rectangle?

Mathematics

1 answer:

AnnZ [28]3 years ago

3 0

Step-by-step explanation:

perimeter=(L+W)2

L=x^2+2x-3

W=2x^2+3x+5

(x^2+2x-3+2x^2+3x+5)2

(x^2+2x^2+2x+3x-3+5)2

(3x^2+5x+2)2

p=(6x^2+10x+4)units

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