If the length of a rectangle in terms of x is x^2+2x-3 and its width is 2x^2+3x+5, what is the perimeter of this rectangle?
1 answer:
Step-by-step explanation:
perimeter=(L+W)2
L=x^2+2x-3
W=2x^2+3x+5
(x^2+2x-3+2x^2+3x+5)2
(x^2+2x^2+2x+3x-3+5)2
(3x^2+5x+2)2
p=(6x^2+10x+4)units
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Step-by-step explanation:
875/5=125
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Answer:
(20+x)*2=x-6
40+2x=x-6
40=-x-6
46=-x
check:
x=-46
20-46*2=-46-6
-26*2=-52
-52=-52
x=-46
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