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aksik [14]
3 years ago
9

If the length of a rectangle in terms of x is x^2+2x-3 and its width is 2x^2+3x+5, what is the perimeter of this rectangle?

Mathematics
1 answer:
AnnZ [28]3 years ago
3 0

Step-by-step explanation:

perimeter=(L+W)2

L=x^2+2x-3

W=2x^2+3x+5

(x^2+2x-3+2x^2+3x+5)2

(x^2+2x^2+2x+3x-3+5)2

(3x^2+5x+2)2

p=(6x^2+10x+4)units

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<h2>Answer:</h2>

By process of elimination, we can eliminate:

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<em>A and C</em> don't work because the given line has it's y-intercept at the origin, therefore, no y-intercept is written. <em>B </em>is not it either because the line <em>does not</em> go <em>down</em> from <em>left to right</em>, therefore, the slope is <em>not</em> negative.

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