I believe the diameter would be 12
d=2r
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what?
Step-by-step explanation:
<h3>Given:</h3>
<h3>To prove:
</h3>
<h3>Solution:</h3>
<u>CM⊥AB - given, therefore</u>
- ∠AMC = 90° and ∠BMC = 90°
<u>Then</u>
- Side CM is common, therefore is congruent to itself
<u>So we have congruent two angles and a side between them on triangles AMC and BMC:</u>
- △AMC ≅ △BMC as per ASA congruency theorem
Answer:
sorry dunno
Step-by-step explanation:
:c
Answer:
AAS I believe
Step-by-step explanation: