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Naily [24]
2 years ago
6

Volume=125 cu ft Length=5 ft Width=?___ Height=5 ft​

Mathematics
1 answer:
Olegator [25]2 years ago
6 0

Answer:

5 ft.

Step-by-step explanation:

First, start with a formula. To find the volume, you have to multiply the length, width, and height.

V = lwh

Plug in the variables that you already know.

125 = 5 ⋅ w ⋅ 5

Simplify.

125 = 25w

Divide both sides by 25 to isolate w.

5 = w

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Fiesta28 [93]

Answer:

ist the question

Step-by-step explanation:

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5 0
3 years ago
What is the area of a circle with a diameter of 24 meters (use 3.14 for Pi)?
Zarrin [17]

The area of a circle is represented by the equation:


A=\pi r^{2}


We know that the diameter is two times the radius: d=2r


So if we know that the diameter of the circle is 24m, we can divide this by two in order to get the radius:


24m=2r -->r=12m


So then we can plug this radius in to the equation for the area of a circle:


A=\pi (12)^{2}


A=144\pi


We are told to use 3.14 as pi, and not pi itself, so let's plug in 3.14 for pi:


A=3.14(144)


A=452.16m^{2}


Now we know that the area of this circle is 452.16 square meters.

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3 years ago
How do i do segment measures
Eduardwww [97]

Asimply measure its length. What else could you measure? After all, length is the only feature a segment has. You’ve got your short, your medium, and your long segments.

Step-by-step explanation:

length

7 0
3 years ago
Evaluate the expression 3(7 + 4)2 − 24 ÷ 6
solong [7]

Answer:

3(7 + 4)2 − 24 ÷ 6 = 62

Step-by-step explanation:

3(7 + 4)2 − 24 ÷ 6 is the given expression.

Now, by the rule of BODMAS, where B = Bracket, O= of, D = divide,

M = multiplication, A = addition and S = subtraction

we try and solve the following expression in the same order.

Solving the bracket first, we get

3<u>(7 + 4)</u>2 − 24 ÷ 6 = 3(<u>11</u>)2 − 24 ÷ 6  =<u> 66</u>  − 24 ÷ 6

Next, we solve divide,

66 − <u>24 ÷ 6</u> = 66 - <u>4</u>  

Next, solving the subtraction, 66 - 4    = 62

Hence, 3(7 + 4)2 − 24 ÷ 6 = 62

6 0
3 years ago
For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr
pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

8 0
3 years ago
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