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Usimov [2.4K]
3 years ago
5

Is 1/5 the same as 5?

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

No, it is not.

Step-by-step explanation:

1/5 is equal to 0.2

5/1 is equal to 5 because there are 5 ones.

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Enter 4/5 and 2/3 as a pair of equivalent fractions with the least common denominator between the two fractions.
Rom4ik [11]

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12/15 and 6/15

Step-by-step explanation:

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the explanaition of the answer and solution is in the picture, check it out. this is for question 14

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What is 1.86 divided by 0.15 and why? ​
ch4aika [34]

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Step-by-step explanation:

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Laura randomly pulled a marble from a bag and then replaced it.
marissa [1.9K]

Answer: C. 180 times

Step-by-step explanation:

From the 60 trials, the percentage of times Laura picked a green marble was:

= 100% - Percentage of times blue and red were picked

= 100% - 25% - 15%

= 60%

If these results were repeated with 300 trials, the number of times Laura would be expected to pick green would be:

= 60% * 300

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3 0
3 years ago
According to a study conducted by the Toronto-based social media analytics firm Sysomos, of all tweets get no reaction. That is,
Svetllana [295]

Answer:

a) E(X) = 71

b) V(X) = 20.59

Sigma = 4.538

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>According to a 2010 study conducted by the Toronto-based social media analytics firm Sysomos, 71% of all tweets get no reaction. That is, these are tweets that are not replied to or retweeted (Sysomos website, January 5, 2015). </em>

<em> Suppose we randomly select 100 tweets. </em>

<em>a) What is the expected number of these tweets with no reaction? </em>

<em>b) What are the variance and standard deviation for the number of these tweets with no reaction?</em>

This can be modeled with the binomial distribution, with sample size n=100 and p=0.71, as the probability of no reaction for each individual tweet.

The expected number of these tweets with no reaction can be calcualted as the mean of the binomial random variable with these parameters:

E(X)=n\cdot p=100\cdot 0.71=71

The variance for the number of these tweets with no reaction can be calculated as the variance of the binomial distribution:

V(X)=np(1-p)=100\cdot0.71\cdot0.29=20.59

Then, the standard deviation becomes:

\sigma=\sqrt{V(X}=\sqrt{20.59}=4.538

5 0
3 years ago
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