Question

A line passes through (3, –2) and (6, 2).

Answer 1

Answer with explanation:

It is given that line passes through two points (3, –2) and (6, 2).

Equation of line in point slope form with the help of formula:

     $\rightarrow \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\rightarrow \frac{y+2}{x-3}=\frac{2+2}{6-3}\\\\\rightarrow \frac{y+2}{x-3}=\frac{4}{3}-------\text{Equation for the line in point-slope form}\\\\\rightarrow 3y+6=4 x-12\\\\\rightarrow 4 x-3 y=6+12\\\\\rightarrow 4 x-3 y=18$

Standard form of line

  4 x-3 y=18

Answer 2

A. Y= 4/3x + -6

B. 4/3x + -1y = 6

2=6* 4/3+b
2=8+b
-6=b