The expression will be 589/15
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
10.89
Step-by-step explanation:
Circle:
C = TTD
C = TT(6.6)
C = 20.73451151
C = 20.73
Triangle:
A = bh/2
A = 6.6(3.3)/2 6.6/2=3.3
A = 21.78/2
A = 10.89
Shaded Region = 10.89
Answer:
EA
Step-by-step explanation: