Answer:
answer is 10/3 thats the answer
The absolute and relative cost difference in the restaurant and copycat meal are :
- Copycat meal is $4.20 less than restaurant meal
- Restaurant meal cost 1.88 times as much as copycat meal
- Copycat meal is 53% of the cost of restaurant meal
Cost of restaurant meal = $8.95
Cost of copycat version = $4.75
1.)
Difference in cost of meal for both version :
Cost of restaurant meal - Cost of copycat version
($8.95 - $4.75) = $4.20.
The copycat meal is $4.20 less than the restaurant meal
2.)
Cost of restaurant meal ÷ Cost of copycat version
($8.95 ÷ $4.75) = 1.884 = 1.88(2 decimal places)
The restaurant meal cost 1.88 times as much as the copycat meal
3.)
Percentage = (8.95 - 4.75) × 100% = 53.07% = 53%(nearest whole number)
The copycat meal is 53% of the cost of restaurant meal
Therefore, the relative and absolute cost difference are $4.20, 1.88 times and 53%
Learn more :brainly.com/question/13218948
Answer:
Q=4
15q-16=8q+12
7q-16=12
7q=28
Q=4
Answer:
the answer is $40.5
Step-by-step explanation:
the basic formula of finding our interest is I = PxRxT
P (principal) = 675
R (rate) = 10% (we have to turn it into a decimal which is 0.010)
T (time) = 6 years
so :
I = 675 x 0.010 x 6
I = 40.5
Answer:
a). The mean = 1000
The variance = 999,000
The standard deviation = 999.4999
b). 1000 times , loss
Step-by-step explanation:
The mean of geometric distribution is given as , 
And the variance is given by, 
Given : 
= 0.001
The formulae of mean and variance are :



a). Mean = 
=
= 1000
Variance = 
= 
= 999,000
The standard deviation is determined by the root of the variance.

=
= 999.4999
b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.
When we win the profit is 500 - 1 = 499
When we lose, the profit is -1
Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

= $ 0.50
Since the answer is negative, we are expected to make a loss.